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x^2-16x-612=0
a = 1; b = -16; c = -612;
Δ = b2-4ac
Δ = -162-4·1·(-612)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-52}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+52}{2*1}=\frac{68}{2} =34 $
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